well i'm a 16 year old kid still in high school and i think i found a new formula but my teachers think its irrelavant but i thing otherwise
Eb = # of edges on a base
Ef = # of edges on a face
E = # of edges
this formula works only for prisms and pyramids
Eb(Ef-1)=E
This one works for the dodecahedron and icosahedron
Eb(Ef-1)+(2Eb)=E
I need an opinion to know if its relevant
In article
<6383934.1208188275147.JavaMail.jakarta@nitrogen.mathforum.org>,
> well i'm a 16 year old kid still in high school and i think i found a new
> formula but my teachers think its irrelavant but i thing otherwise
[quoted text clipped - 12 lines]
>
> I need an opinion to know if its relevant
There are difficulties.
For prisms and pyramids, different faces have different numbers of
edges. so "Ef" might have different values.
For the dodecahedron and icosahedron, Ef is well-defined, but what is Eb?
-----------------------------------------
Searching for a relation between V, E, and F - the numbers of vertices,
edges, and faces of a polyhedron - might be a better way.

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Christopher J. Henrich
chenrich@monmouth.com
htp://www.mathinteract.com
Michael D'Urso - 15 Apr 2008 20:25 GMT
To what i know there really isn't a base for it except parallel plains make a base except pyramids
Eb = # of edges on a base
Ef = # of edges on a face
E = # of edges
F= # of faces
this formula works only for prisms and pyramids
Eb(Ef-1)=E
This one works for the dodecahedron and octahedron
Eb(Ef-1)+(2Eb)=E
For laughs works on the icosahedron
F+10=E