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Math Forum / Math Software / Maple / October 2008



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An exact simplification challenge - 72 (MeijerG)

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Vladimir Bondarenko - 23 Oct 2008 09:00 GMT
Hello,

MeijerG[{{1}, {5/4, 7/4}}, {{1/2, 1, 1}, {}}, 1]

                      ?

Best wishes,

Vladimir Bondarenko

Co-founder, CEO, Mathematical Director

http://www.cybertester.com/  Cyber Tester Ltd.

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Vladimir Bondarenko - 24 Oct 2008 09:36 GMT
> Hello,
>
[quoted text clipped - 16 lines]
>
> ------------------------------------------------

A bit of hint...

4*(Sqrt[1 + Sqrt[2]]*something,

something = ?

;)
sashap - 24 Oct 2008 22:55 GMT
> Hello,
>
> MeijerG[{{1}, {5/4, 7/4}}, {{1/2, 1, 1}, {}}, 1]
>
>                        ?

In[137]:= FullSimplify[
RootReduce[
 Limit[FunctionExpand[
   MeijerG[{{1}, {5/4, 7/4}}, {{1/2, 1, 1}, {}}, x]], x -> 1]]]

Out[137]= (2*2^(3/4)*(Sqrt[2 + Sqrt[2]]*
     ArcTan[Sqrt[2*(1 + Sqrt[2])]] -
    Sqrt[2 - Sqrt[2]]*Log[1 + Sqrt[2] + Sqrt[2*(1 + Sqrt[2])]]))/
Sqrt[Pi]

Cheers,
Oleksandr

> Best wishes,
>
[quoted text clipped - 10 lines]
>
> ------------------------------------------------
clicliclic@freenet.de - 25 Oct 2008 12:13 GMT
sashap schrieb:

> In[137]:= FullSimplify[
>  RootReduce[
[quoted text clipped - 5 lines]
>      Sqrt[2 - Sqrt[2]]*Log[1 + Sqrt[2] + Sqrt[2*(1 + Sqrt[2])]]))/
>  Sqrt[Pi]

The simplifier might have pulled out the factor 2^(1/4) from the
nested roots and written this as

 4*(Sqrt[Sqrt[2]+1]*A - Sqrt[Sqrt[2]-1]*L)/Sqrt[Pi].

Martin.
 
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