> > Bounded Arithmetic
>
[quoted text clipped - 5 lines]
>
> MoeBlee
All right. Let me try to be sure I get this right.
Bounded arithmetic has all the axioms of Robinson arithmetic, plus
every instance of the induction schema where all the quantifiers are
bounded.
To make it stronger, add exponentiation to the language with the
obvious axioms. Now add every instance of the induction schema where
all the quantifiers are bounded in the new language. This is
Exponential Function Arithmetic, or EFA.
Now we can add superexponentiation, and supersuperexponentiation, and
so on. Each theory in this hierarchy can prove the consistency of the
theory two levels down. If you take the union of all these theories,
you get the deductive closure of PRA in classical logic. Sigma-1-
induction arithmetic is conservative over this theory for pi-1-
sentences. Then you have sigma-2-induction arithmetic, sigma-3-
induction arithmetic, and so on, and the union of all these theories
is PA.
A useful way of thinking about the strength of these theories is in
terms of the provably total recursive functions. The provably total
recursive functions of PA are those with level less than epsilon-zero
in the Wainer hierarchy. You can interpret PA in a theory which is
"logic-free" like PRA and has symbols for all these functions. There
is a good description of this in "Proof Theory" by Kurt Schutte.
I think also, considering the tower of theories starting with Bounded
Arithmetic, EFA, and so on, there are "logic-free" counterparts for
these theories along the lines of PRA over which they are at least
pi-1-conservative. With Bounded Arithmetic we would have the symbols
for the polynomial-time-computable functions (polynomial-time-
computable using base 1 notation), then for EFA we would have symbols
for the elementary recursive functions, and so on, increasing in
computational complexity as we move up the tower. I'm not sure about
this part of it, however. I'd like to know more about this topic,
particularly about the relationship between the intuitionistic
versions of these theories, the classical versions of these theories,
and the "logic-free" versions of these theories. But the impression I
get is that the differences are not that important.
Bounded Arithmetic can be interpreted in Robinson Arithmetic. A good
discussion of theories which can be interpreted in Robinson Arithmetic
is in Edward Nelson's "Predicative Arithmetic", which is available for
free at his website.
Edward Nelson is the most extreme mathematical skeptic that I know of.
In "Predicative Arithmetic" he reports his attempts to prove in
Bounded Arithmetic that exponential is not total. This would imply
that EFA is inconsistent.
Bounded Arithmetic is just about the weakest system in which we can do
any reasonable amount of mathematics.
abo - 29 Jan 2008 06:21 GMT
> Bounded Arithmetic is just about the weakest system in which we can do
> any reasonable amount of mathematics.
There is no sense to your thread's title or to this remark. The
strength of systems is not a well-ordering, and among a class of
systems there may not be a "weakest" system.
Rupert - 29 Jan 2008 06:31 GMT
> > Bounded Arithmetic is just about the weakest system in which we can do
> > any reasonable amount of mathematics.
>
> There is no sense to your thread's title or to this remark. The
> strength of systems is not a well-ordering, and among a class of
> systems there may not be a "weakest" system.
The class of systems which logicians generally consider to be
reasonable metatheories in which to reason about object theories is
well-ordered, pretty much, or at any rate certainly well-founded. (You
might consider something like PRA+Con(ZF), perhaps). There might be
some counterexamples, perhaps, such as the weak arithmetic you've been
investigating. It doesn't matter. The title of the thread and my
statement were reasonable.
MoeBlee - 29 Jan 2008 23:34 GMT
> > > Bounded Arithmetic
>
[quoted text clipped - 59 lines]
> Bounded Arithmetic is just about the weakest system in which we can do
> any reasonable amount of mathematics.
Thanks, I'll be reading that over tonight.
MoeBlee