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Math Forum / Math Software / MATLAB / July 2008Find value in an array/matrix
Hi all I was wondering if there is a way to search within a matrix of 2x10 This search would point out a value which has repeated within the same row 3 times. This value could have a variation of +/-0.5. The output of the system would be the average of these three values. thought of using a coulple of if conditions, but I'm not sure how to start. Any suggestions are appreciated This value > could have a variation of +/-0.5. A little clearing up... Do you mean that the values should be the same within .5 or that on different arrays, the values would vary. Maybe provide an example array and what you expect the function to return when it operates on the array. "Matt Fig" <spamanon@yahoo.com> wrote in message <g5m0di$muk$1@fred.mathworks.com>... > This value > > could have a variation of +/-0.5. [quoted text clipped - 3 lines] > values would vary. Maybe provide an example array and what > you expect the function to return when it operates on the array. A) Example: Matrix=[89.5 90 75 23 80 90.2 24 -1 5 101; 44 34 22 -10 43 46 90 2 15 48] output would be: [89.5 90 90.2; 44 34 46] then I would average each row and get the x,y coordinates "Hany R." <hr211@bath.ac.uk> wrote in message <g5q0pm$hr6$1@fred.mathworks.com>... > "Matt Fig" <spamanon@yahoo.com> wrote in message > <g5m0di$muk$1@fred.mathworks.com>... [quoted text clipped - 14 lines] > output would be: [89.5 90 90.2; 44 34 46] > then I would average each row and get the x,y coordinates Additional: the system would work like this -the first row is searched and averaged -second row is searched and averaged -in case that there are to sets with similarities ( 89.5 90 90.2 and 77 77.4 76.8 in the same row) a seperate array or a third row is going to be there. (i'm still working on the algorithm). Each value in this third row is considered the amplitude for both the first and second column, the higher value in the third row, the more likely the x,y values are correct and hence should be chosen. Example: for the above 89.5 90 90.2 77 77.4 76.8 Amp: .2 .1 .5 .01 .02 .3 the first set is chosen (the left hand side i.e. 89.5,...) Thank you > "Hany R." <hr211@bath.ac.uk> wrote in message > <g5q0pm$hr6$1@fred.mathworks.com>... [quoted text clipped - 36 lines] > > Thank you Try to start with something simple. loop through each element, and test the distance to each of the other elements. Compare that distance to your threshold value, and count the number that match. If that number of matches meets your criteria for a cluster, then you're done! Output the indices, or average the answers, or whatever you want to do. In other words, no one can write the code for you, because the problem specification is still somewhat vague. That's ok, you're still trying to figure it out. But the best way to figure it out is to start trying algorithms, writing simple loopy code, until it does what you want. That loopy code can then be used as a description of what you want to do, and we can then help improve the code, vectorize it, simplify it, whatever. -Peter Hi, well, for simplicity, I'm putting part of the code here..where the output is completely correct.. -------------------------------------------------------- FINALMATRIX=[10.1,10.2,5.1,5.2,10.3,5.3,100,55,90,5.4] idx1=1; idx2=1; for ii=1:9; % they are 10 columns, but its covered by 'if' statement eachelem=ii+1; for secondrow=1:10 % to compare each element if eachelem>=11 break; %so it include the 10th end if (abs((FINALMATRIX(1,ii))-(FINALMATRIX (1,eachelem)))) <= 1 % 1m instead of the 0.5 earlier CollectA(1,idx1)=[FINALMATRIX(1,eachelem)]; idx1=idx1+1; %takes each value except the original if secondrow==1; CollectA(1,idx1)=[FINALMATRIX(1,ii)]; % adds up the original element idx1=idx1+1; end end % if calculation eachelem=eachelem+1; end % secondrow end % if ii (columns) --------------------------------------------------------- the output should be [10.1, 10.2, 10.3, 5.1, 5.2, 5.3,5.4] (the order is not an issue.. I'm getting all the values, but some are repeated more than once, so instead of having 7 outputs, I'm getting 11 I'm not sure if the error is from the 'break' command Thanks >I was wondering if there is a way to search within a matrix >of 2x10 >This search would point out a value which has >repeated within the same row 3 times. This value >could have a variation of +/-0.5. Peter Boettcher <boettcher@ll.mit.edu> already replied to your earlier identical question, requesting that you clarify the question. Please respond with your clarifications rather than posting the same unclear question again.  Signature"Do not wait for leaders. Do it alone, person to person." -- Mother Teresa > Hi all > [quoted text clipped - 6 lines] > thought of using a coulple of if conditions, but I'm > not sure how to start. I assume you did not notice my response to your first posting. Please go look for it, read it, and respond under that thread. -Peter |
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