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Math Forum / Mathematics / Undergraduate Math / July 2007



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Simplify cos(x+pi)

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taxidermist@cableone.net - 27 Jul 2007 04:33 GMT
Simplify cos(x+pi)

How do I do this with the addition/subtraction formula?
Brian M. Scott - 27 Jul 2007 04:48 GMT
On Thu, 26 Jul 2007 20:33:05 -0700,
in alt.math.undergrad:

> Simplify cos(x+pi)

> How do I do this with the addition/subtraction formula?

The sum formula for the cosine is

  cos(x + y) = cos(x) cos(y) - sin(x) sin(y),
 
so

  cos(x + pi) = cos(x) cos(pi) - sin(x) sin(pi).
 
You know what cos(pi) and sin(pi) are, so you can substitute
those values into this formula to complete the
simplification.

Brian
Stan Brown - 27 Jul 2007 05:15 GMT
Thu, 26 Jul 2007 23:48:32 -0400 from Brian M. Scott
<b.scott@csuohio.edu>:
> On Thu, 26 Jul 2007 20:33:05 -0700,
> in alt.math.undergrad:
[quoted text clipped - 4 lines]
>
>    cos(x + pi) = cos(x) cos(pi) - sin(x) sin(pi).

And you can check your work by thinking about what relation cos(x+pi)
must bear to cos(x). Since an angle of pi is half a circle, what
geometrical relationship do you see between cos(x+pi) and cos(x)?

Work this out on your own, and then jave a look at my less-than-
beautiful diagram at
   http://oakroadsystems.com/twt/refangle.htm#RelatedIdentities

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Brian VanPelt - 27 Jul 2007 06:45 GMT
>Simplify cos(x+pi)
>
>How do I do this with the addition/subtraction formula?

The sum of two angles formula is cool, but here is another method.

cos(x + pi) = cos[(x + pi/2) + pi/2] = - sin(x + pi/2) = - cos x

This only works for specific angles because cosine is "complementary"
sine.

Brian
Frederick Williams - 27 Jul 2007 08:53 GMT
> >Simplify cos(x+pi)
> >
[quoted text clipped - 3 lines]
>
> cos(x + pi) = cos[(x + pi/2) + pi/2] = - sin(x + pi/2) = - cos x

You may find that the op wants to apply the addition formula to cos[(x +
pi/2) + pi/2]!

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