> y=pi*r^3
> y'=?
> Only do not think, that it is a joke or disrespect
> t for participants of a forum. The EXHAUSTIVE answer
> is necessary to me!
Derivate with respect to what ?
y(r) = pi*r^3 -> dy/dr = pi*3*r^2
y(t) = pi*r(t)^3 -> dy/dt = pi*3*r^2*dr/dt
..
Best wishes
Torsten.
And if y=pi*r^3 - volume of a cone with the height equal to radius?
HallsofIvy - 24 Mar 2009 11:38 GMT
> And if y=pi*r^3 - volume of a cilinder with the
> height equal to radius?
>
> Message was edited by: Mishin
??Then the answer is exactly the same, of course, 3pi r^2 r'. How you got the formula doesn't change its derivative.
yuyukin - 26 Mar 2009 13:02 GMT
http://eqworld.ipmnet.ru/forum/viewtopic.php?f=3&t=134