Math Forum / Mathematics / Algebra Help / December 2006

I need some help in determining how long to cut some picture frame stock for
which I have an already cut piece of glass.
If
L = outside length of the finished frame

Let G be group. A normal subgroup N C G is called minimal if N not =
{e} and
there is no K not = G such that e not= K ( N. Assueme that G is a
finite solvable group

Suppose there are two sequences.
The first one has 20 numbers; the first number is 10 and the last number is
50.
The second has 9 numbers; it begins with 6 and ends with 34.

Hello people. I'm stuck on the following problem:
" in how many ways can 8 boys be divided into 4 sets of 2?"
This is my answer which is wrong according to the answers in the back :
8C2*6C2*4C2*2C2=2520.

Hi all; having some trouble with the following:
A mortgage of $250,000 is to be repaid over 20 years in equal monthly
installments. Suppose the interest rate is 5.2% per annum continuously
compounded. If interest is added at the beginning of the year, find the

I'm working on this basic differential equation:
x' + Ax = f
where, A=
[1 1 2 0]

[e^(ix)+e^(-ix)]/2=cos(x)  =>
[e^(e^(ix))+e^(e^(-ix))]/2=?

I'm not mathematician and just trying to find out how much I'm paying
for my sms and mobile calls to my mobile provider.
Thanks in advance.

[1+2*(x)+x^(2)]+[x^(3)+2*x^(4)+x^(5)]...=0
x=?

sorry, this may be a dumb question AND is not quite algebra...but I
have been unsuccessful finding an answer or even a discussion about
this in a textbook.
Let's say that we need to subtract 23 from 51. We can solve this by

Hi Y'all - basic question (I think) about solving an exponential
equation with the same variable in the base AND the exponent.
Here's the example:
(1+x)^(1/x) = e

I'm trying to calculate a limit with the help of maclaurin series, and
there is something odd. A part of the limit is 1/(Tan(x))^2 x-> 0 .
Checking this series in mathematica gives: 1/x^2-2/3+x^2/15+...
But i was expecting it to be 1/(x^2+...) which would be 1 divided by the

I'm supposed to determine the Maclaurin polynoma of the second order of
the inverse of f(x)=cos(3x)+log(1+2x)-1
The first step should be determining the macluarin polynoma to f(x). It
is: f(x)=1+x^3*B(x)+2x-(2x)^2/2+x^3*B(x)