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Math Forum / Mathematics / Mathematical Logic / October 2008



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ThreadLast Post  Replies
Question regard implication and being a theorem of FOL.22 Oct 2008 03:00 GMT127
Suppose T is a theory of first-order logic. Further suppose P -> Q is
proved using RAA. Now the truth table for P -> Q is:
P   Q    P->Q
0    0    1
WM on the Binary Tree21 Oct 2008 18:37 GMT3
As I see it, WM has clearly made the point that there is a pairing
procedure able to produce a one-one application between nodes and
paths AS the construction of the binary tree goes on. For instance:
                           # (1)
Binary Tree and Pairs of Nodes20 Oct 2008 19:38 GMT144
A path in an infinite binary tree is the representation of a real
number of the interval [0, 1]. (Terminating rational numbers have two
representations each.)
Two paths A and B in the infinite binary tree can be distinguished by
Are these equivalent?20 Oct 2008 19:18 GMT9
1. A(x)(Human(x) -> Mortal(x))
2. E(x)(Human(x) -> Philosopher(x)) /:. E(x)(Human(x) -> (Mortal(x) ^
Philosopher(x)))
Is this equivalent to what would be in category logic:
Is this argument valid, or even a WFF?19 Oct 2008 22:34 GMT8
Is this argument valid, or even a WFF:
1. A(x)(Cat(x) -> (Cute(x) ^ Eats(x, salmon)))
2. Cat(Chloe) /:. Cute(Chloe) ^ Eats(Chloe, salmon)
What about this one:
interpretation19 Oct 2008 17:29 GMT1
is it not true that understanding and common interpretation are
necessary for progress?
Line and Cauldron19 Oct 2008 07:55 GMT5
PROPOSAL
We know that mathematics employs powerful metaphors to bring us ideas
that otherwise might seem alien to us. But is this a misrepresentation
of the role of metaphor in mathematics? Isn't it more the case that
Limit of iterated anti-diagonalization?17 Oct 2008 15:29 GMT7
The usual clueless objection to Cantor's Theorem is to say that you
can just add
the anti-diagonal to the list..  The fact that this results NOT  (as
the newbies mistakenly
The middle of the string16 Oct 2008 19:48 GMT28
There's no left or right in a string of beads. And the middle of a
string of beads is only dependent on our being able to ascertain left
and right. But the string itself doesn't have a left or right: thus, a
middle doesn't belong to a string.
Yet another disproof of the diagonal argument15 Oct 2008 19:56 GMT343
This is a disproof of the "diagonal argument" by induction, although
I'd rather call it a proof of unsoundness: yet another one, that is.
It's actually a shortened version of an argument I have presented in
the thread "A consideration concerning the diagonal argument of G.
'Step', and 'Event'. A distinction.14 Oct 2008 16:59 GMT7
Logical, computer and mechanical operations are not comprised of STEPS.
Steps refer to a task or argument. Rather, such operations are comprised
of discrete, independent, isolated EVENTS. Each event is both a new
start and a finish, with no powers of task representation. It is ...
first order13 Oct 2008 16:05 GMT1
I want to know  why we cannot express omega={ {},{{}},{{},{{}}},...}
in a first order language?
If you know any references (in this case), please let me know.
Regards,
Time Is Space-Continuum.By Aiya-Oba12 Oct 2008 06:59 GMT1
Time is the included middle (equator) of the self-contradiction (pair)
of Space.
               -Aiya-Oba (Poet/Philosopher).
Thus,
boolean algebra11 Oct 2008 10:12 GMT11
Hi, I'm new to boolean algebra and am having a lot of problems
figuring out which identities to use to solve this problem. any help
would be grately appreciated.
Given that:
Is Cardinality a FOL concept?10 Oct 2008 06:42 GMT13
It seems to me that I can create within FOL a predicate that determines
whether a finite set has a particular finite cardinality.
Lets define C_0 being a wff that states a set A is of cardinality zero as:
C_0(A) = (def) a={}
 
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