| Thread | Last Post | Replies |
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| Missing digits | 31 Mar 2007 15:41 GMT | 10 |
How many digits would on average be missing if you draw one digit D times with replacement? Accoring to the simple formula 0.9^Dx10 it would be 3.5 with a std.dev. of 1. But I'm unclear about larger draws such as 22.
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| An Interesting Triangle Center | 30 Mar 2007 16:34 GMT | 2 |
Recently I found an intersting triangle center, that can be viewed at the following URL http://www.geocities.com/alfetc Comments and discussions are welcome. Best regards,
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| Entangled Boxes | 30 Mar 2007 16:34 GMT | 2 |
Something like this was used to explain quantum entanglement in a book by Julian Brown called, Quest for the Quantum Computer: A single black box has: an on-off switch,
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| SOLVE IT | 30 Mar 2007 14:33 GMT | 1 |
find the coefficient of x^5 in (x-1)*(x^2-2)*(x^3-3).............. (x^100-100)
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| Q: A class of numerals | 30 Mar 2007 01:03 GMT | 1 |
1455 base 6 converts to 1103 base 7 1455 base 7 converts to 1103 base 8 1455 base 8 converts to 1103 base 9 ...
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| An exact 1-D limit challenge - 31 | 29 Mar 2007 11:59 GMT | 26 |
Hello all computer algebra knights, ;) None of the modern-generation computer algebra systems can handle this limit straightforwardly limit(2^a*int(cos(ln(z))/(1+z^2)^a, z= 0..infinity),
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| AMM Problem 11280 | 29 Mar 2007 05:21 GMT | 5 |
[Sorry to sci.math - I meant to crosspost this to a.m.r. before.] AMM Readers- Does anyone else find Problem 11280 (in the current issue) kind of screwy? I was about to describe why I think so, but I wish to limit public
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| An exact 1-D integration challenge - 37 | 26 Mar 2007 23:07 GMT | 5 |
Hello all the computer algebra buffs, Most surprisingly, the current generation computer algebra systems fail do calculate this integral directly int(1/sqrt(z^3-I*z^2+z-I), z= -infinity..infinity);
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| looking for "mathematics made difficult" | 26 Mar 2007 14:58 GMT | 1 |
That is a book by Carl Linderholm that seems to be very out of print and hard to find. Does anyone know if the title is available as an ebook or something?
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| A peculiar clock (a geometry puzzle) | 25 Mar 2007 00:10 GMT | 2 |
Good morning to all, As the Beatles sang: with a little help from my friends............. My previous puzzle, about the paper hat, got a surprising turn. The solution I had in mind possibly can be surpassed. But in order to be
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| Cube/Spider Problem Please Help.. | 25 Mar 2007 00:10 GMT | 3 |
Hi everyone..i really need the answer to this problem so i would really appreciate it if you help me..THANKS A spider is standing on vertex (S) in this cube. (The cube's 8 vertices’ are (S,A,G,B,E,D,C,F) [img]http://www1.filehost.to/files/2007-03-20_03/195358_sss.jpg[/img] The ...
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| An exact 1-D integration challenge - 36 | 23 Mar 2007 15:24 GMT | 14 |
Hello the computer algebra fans, Using Maple/Mathematica operations, can you calculate the exact value of this integral int(1/(1+cos(z)^10), z= 0..Pi);
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| 6/25=.24, 6/24=.25 | 22 Mar 2007 10:03 GMT | 5 |
While noodling around with a calculator, I noticed the coincidence that 6/25 = .24, while 6/24 = .25. Are there any more coincidences like this? One way of looking at it is that we have two integer equations
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| An exact 1-D limit challenge - 30 | 21 Mar 2007 12:05 GMT | 10 |
Hello all the symbolic star girls and machos, ;) None of the current generation computer algebra systems can calculate this limit limit(int(z^a/(exp(z)-1)^a, z=0..infinity), a=infinity);
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| A4 to square | 20 Mar 2007 18:08 GMT | 2 |
This problem is so simple, that it may be known already: How to cut an A4 sheet of paper into 3 pieces, which can be reassembled as a square? Compasses and cm-ruler.
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