| Thread | Last Post | Replies |
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| JSH: The circular argument | 28 Apr 2008 23:58 GMT | 13 |
If you ask people how we know that mathematicians do not lie about mathematics, usually you get the answer that other mathematicians would tell you if they did!!! But what if MOST mathematicians lie about research?
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| a triangle | 28 Apr 2008 18:32 GMT | 4 |
Let T be a triangle of area 6 square inches and perimeter 12 inches. Show that the triangle T can be cut into 2006 triangles each of which has perimeter strictly larger than 6 inches.
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| end points of a curve | 27 Apr 2008 16:10 GMT | 3 |
i've got such a problem. imagine a curve-partly linear, partly non-linear. it can be for example part of a circle like ')' or like '(' or like 'U'. what i need is to write fully automatic algorithm that will find left and right end-points of the curve. as You can see i cannot do ...
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| I Want to BUY SOLUTUION MANUAL for << Quantum Mechanics: An Accessible Introduction by Robert Scherrer >> | 26 Apr 2008 17:54 GMT | 1 |
I Want to BUY SOLUTUION MANUAL for << Quantum Mechanics: An Accessible Introduction by Robert Scherrer >> If u have it pls reply to my post. I will pay u via paypal.
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| zaobarthh@yahoo.com | 25 Apr 2008 21:18 GMT | 1 |
zaobarthh@yahoo.com zaobarthh@yahoo.com You have hurt many people, intentionally, with great meanness. You must make amends to try to avoid being damned for eternity. But that may
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| How Many Sugar Grains in a Five Pound Bag of Sugar? | 25 Apr 2008 05:05 GMT | 9 |
Would anybody here happen to know this question: How many grains of sugar are in a five pound bag of sugar? If not, would you happen to know where I can find out? Thanks!
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| locus | 22 Apr 2008 13:02 GMT | 3 |
-------------------------------------------------------------------------------- a variable circle passes thrpugh a fixed point and cuts a fixed circle at the ends of a variable diameter of the fixed circle. Show that the locus of the centre of the variable circle is a straight ...
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| A lot of Solutions Manual in Electronic (PDF)Format! | 22 Apr 2008 06:55 GMT | 1 |
A lot of Solution Manual in Electronic (PDF)Format! A lot of Solutions Manuals in Electronic (PDF)Format! Just contact with trustsolution (at) hotmail.com (my email address), these are parts of our solutions, if the solution you want isn’t on the list,
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| Solution Manual for Electric Circuits by Nilsson and Riedel | 20 Apr 2008 05:02 GMT | 3 |
If anyone has the solutions and coul email them to me at mapuha720@yahoo.com , that would be greatly appreciated. Thanks :)
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| JSH: James Harris Surrogate Factors RSA-100 | 19 Apr 2008 04:48 GMT | 37 |
About ten days ago, James Harris was kind enough to share with me the latest version of his surrogate factoring program, written in Java. James and I agreed that James would refrain from posting to
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| A lot of Solution Manuals in Electronic (PDF)Format! | 18 Apr 2008 10:08 GMT | 1 |
A lot of Solution Manuals in Electronic (PDF)Format! A lot of Solutions Manuals in Electronic (PDF)Format! Just contact with trustsolution (at) hotmail.com (my email address), these are parts of our solutions, if the solution you want isn’t on the list,you
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| 2500 Availables solutions manuals | 17 Apr 2008 18:08 GMT | 4 |
My List of Solutions Manual ____________________________ contact me to : mattosbw1@gmail.com mattosbw1(at)gmail.com
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| Not a collage kid but got a new idea | 15 Apr 2008 20:25 GMT | 3 |
well i'm a 16 year old kid still in high school and i think i found a new formula but my teachers think its irrelavant but i thing otherwise Eb = # of edges on a base Ef = # of edges on a face E = # of edges
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| Not sure | 15 Apr 2008 18:27 GMT | 3 |
well i'm a 16 year old kid still in high school and i think i found a new formula but my teachers think its irrelavant but i think otherwise. Its how to find the # of edges but euler has a type of formula Eb = # of edges on a base Ef = # of edges on a face E = # of edges
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| If K is a subgroup of G of order p^k, show that K is subgroup of H | 15 Apr 2008 18:21 GMT | 2 |
Let |G| = (p^n)m where p is prime and gcd(p,m) = 1. Suppose that H is a normal subgroup of G of order p^n. If K is a subgroup of G of order p^k, show that K is subgroup of H. Okay, I wonder if there is more I need to do, or if I need to prove they are finite. I feel like I am ...
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